博客
关于我
LeetCode---Delete Node in a Linked List
阅读量:606 次
发布时间:2019-03-12

本文共 1254 字,大约阅读时间需要 4 分钟。

237. Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = [4,5,1,9], which looks like following:

 

Example 1:

Input: head = [4,5,1,9], node = 5Output: [4,1,9]Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.

Example 2:

Input: head = [4,5,1,9], node = 1Output: [4,5,9]Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.

Note:

  • The linked list will have at least two elements.
  • All of the nodes' values will be unique.
  • The given node will not be the tail and it will always be a valid node of the linked list.
  • Do not return anything from your function.

请编写一个函数,使其可以删除某个链表中给定的(非末尾)节点,你将只被给定要求被删除的节点。

思路:现在只给了当前节点,那么只能将后一节点的值赋给当前节点,将后一节点删掉,则相当于删掉了“当前节点”。

# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def deleteNode(self, node):        """        :type node: ListNode        :rtype: void Do not return anything, modify node in-place instead.        """        node.val=node.next.val        node.next=node.next.next

 

转载地址:http://hxhxz.baihongyu.com/

你可能感兴趣的文章
mysql复制表结构和数据
查看>>
mysql复杂查询,优质题目
查看>>
MySQL外键约束
查看>>
MySQL多表关联on和where速度对比实测谁更快
查看>>
MySQL多表左右连接查询
查看>>
mysql大批量删除(修改)The total number of locks exceeds the lock table size 错误的解决办法
查看>>
mysql如何做到存在就更新不存就插入_MySQL 索引及优化实战(二)
查看>>
mysql如何删除数据表,被关联的数据表如何删除呢
查看>>
MySQL如何实现ACID ?
查看>>
mysql如何记录数据库响应时间
查看>>
MySQL子查询
查看>>
Mysql字段、索引操作
查看>>
mysql字段的细节(查询自定义的字段[意义-行列转置];UNION ALL;case-when)
查看>>
mysql字段类型不一致导致的索引失效
查看>>
mysql字段类型介绍
查看>>
mysql字段解析逗号分割_MySQL逗号分割字段的行列转换技巧
查看>>
MySQL字符集与排序规则
查看>>
MySQL字符集乱码
查看>>
mysql存储IP地址的数据类型
查看>>
mysql存储中文 但是读取乱码_mysql存储中文乱码
查看>>